Assertion A: If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm.
Reason R: Least Count = Pitch / (Total divisions on circular scale)
In the light of the above statement, choose the most appropriate answer from the options given below:
Assertion A: If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm.
Reason R: Least Count = Pitch / (Total divisions on circular scale)
In the light of the above statement, choose the most appropriate answer from the options given below:
Option 1 -
A is correct but R is not correct.
Option 2 -
A is not correct but R is correct
Option 3 -
Both A and R are correct and R is NOT the correct explanation of A.
Option 4 -
Both A and R are correct and R is the correct explanation of A.
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1 Answer
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Correct Option - 3
Detailed Solution:Least count = Pitch / (Total divisions on circular scale)
In 5 revolution, distance travelled = 5mm
? In 1 revolution, distance travelled = 1mm
So least count = 1/50 = 0.02mm = 0.002 cm
So, Assertion is not correct but reason is correct
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