Assertion A: If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm.
Reason R: Least Count = Pitch / (Total divisions on circular scale)

In the light of the above statement, choose the most appropriate answer from the options given below:

Option 1 - <p>A is correct but R is not correct.</p>
Option 2 - <p>A is not correct but R is correct</p>
Option 3 - <p>Both A and R are correct and R is NOT the correct explanation of A.</p>
Option 4 - <p>Both A and R are correct and R is the correct explanation of A.</p>
1 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
V
7 months ago
Correct Option - 3
Detailed Solution:

Least count = Pitch / (Total divisions on circular scale)
In 5 revolution, distance travelled = 5mm
? In 1 revolution, distance travelled = 1mm
So least count = 1/50 = 0.02mm = 0.002 cm
So, Assertion is not correct but reason is correct

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Physics Units and Measurement 2025

Physics Units and Measurement 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering