Assume that a tunnel is dug along a chord of the earth, at a perpendicular distance (R/2) from the earth's centre, where 'R' is the radius of the Earth. The wall of the tunnel is frictionless. If a particle is released in this tunnel, it will execute a simple harmonic motion with a time period

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>2</mn> <mi>π</mi> <mroot> <mrow> <mfrac> <mrow> <mi>R</mi> </mrow> <mrow> <mi>g</mi> </mrow> </mfrac> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mi>g</mi> </mrow> <mrow> <mn>2</mn> <mi>π</mi> <mi>R</mi> </mrow> </mfrac> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> <mi>π</mi> </mrow> </mfrac> <mroot> <mrow> <mfrac> <mrow> <mi>g</mi> </mrow> <mrow> <mi>R</mi> </mrow> </mfrac> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>2</mn> <mi>π</mi> <mi>R</mi> </mrow> <mrow> <mi>g</mi> </mrow> </mfrac> </mrow> </math> </span></p>
10 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
P
7 months ago
Correct Option - 1
Detailed Solution:

F = m E cos θ

 =m (GMR3*r)*xr ma=mgR*a=gRx

T = 2 π R g

 

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Physics Gravitation 2025

Physics Gravitation 2025

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