Before connecting the circuit shown in figure all capacitors were uncharged. The circuit now is in steady state. Now the switch $S$  is closed. During the time the steady state is reached again:

Column?I	Column?II
i. Charge on C1	p. increases
ii. Charge on C2	q. decreases
iii. Charge on C3	r. remains same
iv. Charge on C4	s. becomes zero

Now, match the given columns and select the correct option from the codes given below.

Codes:

 

Correct Option - 2


Detailed Solution:

Before closing the switch

After closing the switch

So charge on C₁  remains same, on C₂ increases and on C₃ and C₄  decreases.

<p>Before closing the switch</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1758255501phpAL0wHV.jpeg" alt="" width="174" height="143" loading="lazy"></picture></div></div><p>After closing the switch</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1758255501phpAL0wHV.jpeg"4 alt="" width="177" height="133" loading="lazy"></picture></div></div><p>So charge on C₁ &lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1819781171"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;remains same, on C₂&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1026" DrawAspect="Content" ObjectID="_1819781172"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt; increases and on C₃ and C₄&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1028" DrawAspect="Content" ObjectID="_1819781174"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;decreases.</p>

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