Block A of weight 100 N rests on a frictionless inclined plane of slope angle 30° (Fig. 5.7). A flexible cord attached to A passes over a frictionless pulley and is connected to block B of weight W. Find the weight W for which the system is in equilibrium.
This is a Short Answer type Questions as classified in NCERT Exemplar
Explanation- in equilibrium, The force mgsinacting on the block A is parallel to the plane should be balanced by the tension in the string
mgsin
and for block B, w=T=F
from these two above equation
w=mgsin= 100sin30= 100 (1/2)=50N
<p><span lang="EN-IN">This is a Short Answer type Questions as classified in NCERT Exemplar</span></p><p><strong><span lang="EN-IN">Explanation- </span></strong><span lang="EN-IN">in equilibrium, The force mgsin<span contenteditable="false"> <math> <mi>θ</mi> </math> </span></span><span lang="EN-IN">acting on the block A is parallel to the plane should be balanced by the tension in the string</span></p><p><span lang="EN-IN">mgsin<span contenteditable="false"> <math> <mi>θ</mi> <mo>=</mo> <mi>T</mi> <mo>=</mo> <mi>F</mi> </math> </span></span><span lang="EN-IN"><!- [endif]-></span><!- [endif]-></p><p><span lang="EN-IN">and for block B, w=T=F</span></p><p><span lang="EN-IN"> from these two above equation </span></p><p><span lang="EN-IN">w=mgsin<span contenteditable="false"> <math> <mi>θ</mi> </math> </span></span><span lang="EN-IN">= 100sin30= 100 (1/2)=50N</span></p>
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