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Calculate the number of atoms in 39.4 g gold. Molar mass of gold is 197g mole-1.

0 2 Views | Posted 4 months ago
Asked by Shiksha User

  • 1 Answer

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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    This is a short answer type question as classified in NCERT Exemplar

    molar mass = mass of avogadro’s number of atoms= 6.023 × 10 23 atoms.

    197 g of gold contains =6.023 × 10 23 a t o m s

    1g of gold contain= 6.023 × 10 23 197 atoms

    39.4 g of gold atoms = 6.023 × 10 23 × 39.4 197 = 1.2 × 10 23 atoms

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