Choose the correct waveform that can represent the voltage across R of the following circuit, assuming the diode is ideal one:

 

Correct Option - 2


Detailed Solution:

Diode, in forward biased condition only, will allow current to flow through it.

Pot. different across resistor is

$\Delta V=\left(10sin\omega t-3\right)volt$

But in reverse biased condition of diode,

$\Delta V=0$     (across diode)

 

<p>Diode, in forward biased condition only, will allow current to flow through it.</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1754390821phpYbtFUU.jpeg" alt="" width="250" height="131" loading="lazy"></picture></div><div>Pot. different across resistor is</div><div><span contenteditable="false"> <math> <mrow> <mi>Δ</mi> <mi>V</mi> <mo>=</mo> <mrow> <mo> (</mo> <mrow> <mn>1</mn> <mn>0</mn> <mi>s</mi> <mi>i</mi> <mi>n</mi> <mi>ω</mi> <mi>t</mi> <mo>−</mo> <mn>3</mn> </mrow> <mo>)</mo> </mrow> <mi>v</mi> <mi>o</mi> <mi>l</mi> <mi>t</mi> </mrow> </math> </span></div><div>But in reverse biased condition of diode, </div><div><span contenteditable="false"> <math> <mrow> <mi>Δ</mi> <mi>V</mi> <mo>=</mo> <mn>0</mn> </mrow> </math> </span>&nbsp; &nbsp; (across diode)</div></div><p>&nbsp;</p>

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