Consider a binary star system of star A and star B with masses mA and mB revolving in a circular orbit of radii rA and rB, respectively. If TA and TB are the time period of star A and star B, respectively, then:

Option 1 -

TA = TB

Option 2 -

TA > TB (if mA > mB)

Option 3 -

T A T B = ( r A r B ) 3 2

Option 4 -

TA > TB (if rA > rB)

0 3 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    Since binary mass system performs circular motion about is common centre of mass, so

    m A ω A 2 r A = G m B m A ( r A + r B ) 2 = G m B m A r 2

    m A ω A 2 × m B ( m A + m B ) r = G m B m A r 2

    ω A = G ( m A + m B ) r 3

    Similarly we can show that

    ω B = G ( m A + m B ) r 3

    Hence their angular velocity will be same, time period will be same, i.e. TA = TB

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