Consider a pair of identical pendulums, which oscillate with equal amplitude independently such that when one pendulum is at its extreme position making an angle of 2° to the right with the vertical, the other pendulum makes an angle of 1° to the left of the vertical. What is the phase difference between the pendulums?

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Payal Gupta | Contributor-Level 10

7 months ago

This is a short answer type question as classified in NCERT Exemplar

By considering the diagram

_{$θ$ 1}= $θ_{o} s i n (w t + \emptyset_{1})$

_{$θ$ 2}= $θ_{o} s i n ? (w t + \emptyset_{2})$

As it is clear given that amplitude time period being equal but phases being different. Now for first pendulum at any time t

_{$θ$ 1}= $θ$ ₂

So sin $\frac{π}{2}$ = sin(wt+ $\emptyset_{1}$ )

wt+ $\emptyset_{1} = \frac{π}{2}$

where $θ$ _o=2^o is the angular amplitu

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Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen 2025

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