Consider a sample of oxygen behaving like an ideal gas. At 300K, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be :
(Molecular weight of oxygen is 32 g/mol ; R = 8.3 JK-1 mol-1)
Consider a sample of oxygen behaving like an ideal gas. At 300K, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be :
(Molecular weight of oxygen is 32 g/mol ; R = 8.3 JK-1 mol-1)
Option 1 - <p>√(8π/3)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>√(8/3)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>√(3/3)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>√(3π/8)</p>
3 Views|Posted 5 months ago
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5 months ago
Correct Option - 4
Detailed Solution:
v_rms = √ (3RT/M) and v_av = √ (8RT/πM)
⇒ v_rms / v_av = √ [ (3RT/M) / (8RT/πM)] = √ (3π/8)
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physics ncert solutions class 11th 2023
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