Consider a uniform cubical box of side a on a rough floor that is to be moved by applying minimum possible force F at a point b above its centre of mass (see figure). If the coefficient of friction is μ = 0.4 , the maximum possible value of 100 × b a  for box not to topple before moving is

 

0 3 Views | Posted 2 months ago
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    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago

    For no toppling

    F a 2 + b m g a 2

    μ a 2 + μ b a 2

    0.2 a + 0.4 b 0.5 a

    0.4 b 0.3 a

    b 3 a 4

    b 0.75 a (in limiting case)

    But is not possible as maximum value of b can be equal to 0.5 a only.

    100 b a m a x = 50.00

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