Consider a wire carrying a steady current, I placed in a uniform magnetic field B perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do not work. This implies that,
(a) motion of charges inside the conductor is unaffected by B, since they do not absorb energy.
(b) Some charges inside the wire move to the surface as a result of B.
(c) If the wire moves under the influence of B, no work is done by the force.
(d) If the wire moves under the influence of B, no work is done by the magnetic force on the ions, assumed fixed within the wire.
Consider a wire carrying a steady current, I placed in a uniform magnetic field B perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do not work. This implies that,
(a) motion of charges inside the conductor is unaffected by B, since they do not absorb energy.
(b) Some charges inside the wire move to the surface as a result of B.
(c) If the wire moves under the influence of B, no work is done by the force.
(d) If the wire moves under the influence of B, no work is done by the magnetic force on the ions, assumed fixed within the wire.
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (b, d)
Explanation- F=IlB, the direction of force is given by fleming's left hand rule and F is perpendicular to the direction of magnetic field. So work done is zero.
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