A ring of mass m and radius r rotates about an axis passing through its centre and perpendicular to its plane with angular velocity σ ). Its kinetic energy is

 

Option 1 - <p>a</p>
Option 2 - <p>b</p>
Option 3 - <p>c</p>
Option 4 - <p>d</p>
3 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
R
4 months ago
Correct Option - 1
Detailed Solution:

Kinetic energy = 1 2 I ω 2 , and for ring   I = m r 2

Hence K E = 1 2 m r 2 ω 2

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Physics System of Particles and Rotational Motion 2025

Physics System of Particles and Rotational Motion 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering