Figure 14.2. shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated on the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is

(a) x (t) = B sin(2 π t 30 )

(b) x (t) = B cos(πt/15)

(c) x (t) = B sin( π t 15 + π 2 )

(d) x (t) = Bcos ( π t 15 + π 2 )

3 Views|Posted 7 months ago
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7 months ago

This is a multiple choice answer as classified in NCERT Exemplar

(a) Let angular velocity of the particle executing circular motion is w and when it is at O makes and angle θ

As θ =wt

OR=OQCos (90- θ )

= OQsin θ =OQsinwt

=rsinwt

x=rsinwt=Bsinwt

= Bsin 2 π T t =Bsin ( 2 π 30 t )

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Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen 2025

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