Figure 14.2. shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated on the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is

(a) x (t) = B sin(2 $\frac{π t}{30}$ )

(b) x (t) = B cos(πt/15)

(c) x (t) = B sin( $\frac{π t}{15} + \frac{π}{2}$ )

(d) x (t) = Bcos ( $\frac{π t}{15} + \frac{π}{2}$ )

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Answered by

Payal Gupta | Contributor-Level 10

4 months ago

This is a multiple choice answer as classified in NCERT Exemplar

(a) Let angular velocity of the particle executing circular motion is w and when it is at O makes and angle $θ$

As $θ$ =wt

OR=OQCos (90- $θ$ )

= OQsin $θ$ =OQsinwt

=rsinwt

x=rsinwt=Bsinwt

= Bsin $\frac{2 π}{T} t$ =Bsin ( $\frac{2 π}{30} t$ )

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