Figure shows (v_x ,t) and (v_y,t) diagrams for a body of unit mass. Find the force as a function of time.

This is a Long Answer type Questions as classified in NCERT Exemplar

Explanation- v_x=2t for 0

= 2 (2-t) for 1

=0 for t>2s

V_y= t for 0

= 1 for t>1s

F_x= ma_x= mdv_x/dt= 1 (2)

F_y = ma_y= mdv_y/dt

= 1 (1) for 0

F= F_x? +F_y?

= 2? +?

=-2?

=0

<p>This is a Long Answer type Questions as classified in NCERT Exemplar</p><p><strong>Explanation-</strong> v_x=2t for 0&lt;t&lt;1s&lt; p=""&gt; &lt;/t&lt;1s&lt;&gt;</p><p>= 2 (2-t) for 1&lt;t&lt;2s&lt; p=""&gt; &lt;/t&lt;2s&lt;&gt;</p><p>=0 for t&gt;2s</p><p>V_y= t for 0&lt;t&lt;1s&lt; p=""&gt; &lt;/t&lt;1s&lt;&gt;</p><p>= 1 for t&gt;1s</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1745403052phpB3zEHB_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1745403052phpB3zEHB.jpeg" alt="" width="280" height="118"></picture></div></div><p>F_x= ma_x= mdv_x/dt= 1 (2)</p><p>F_y= ma_y= mdv_y/dt</p><p>= 1 (1) for 0&lt;t&lt;1s=0for1&lt;t&lt; p=""&gt; &lt;/t&lt;1s=0for1&lt;t&lt;&gt;</p><p>F= F_x? +F_y? </p><p>= 2? +? </p><p>=-2? </p><p>=0</p>

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