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Find current through zener diode if its breakdown voltage is 5V.

 

Option 1 -

58.33 mA

Option 2 -

25 mA

Option 3 -

28.33 mA

Option 4 -

20.23 mA

0 2 Views | Posted 6 days ago
Asked by Shiksha User

  • 1 Answer

  • Correct Option - 1


    Detailed Solution:

    i b a t t e r y = ( 2 0 − 5 ) 2 0 0 = 1 5 2 0 0 A

    i 3 0 0 Ω = 5 3 0 0 A

    i z e n e r = 1 5 2 0 0 − 5 3 0 0  

    = 58.33 mA

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