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Alternating Current Overview Physics Alternating Current Physics Class 12th

For a series LCR circuit with R = 100 $Ω$ , L = 0.5mH and C = 0.1 pF connected across 220V – 50Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is:

Option 1 -

$\approx 90 °,$ predominantly inductive circuit

Option 2 -

0°, resonance circuit

Option 3 -

$\approx 90 °,$ predominantly capacitive circuit

Option 4 -

0°, resistive circuit

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 3

Detailed Solution:

$ω = 100 π, R = 100 Ω, X_{L} = L ω = 0.5 \times 1 0^{- 3} \times 100 π = 5 π \times 1 0^{- 2} Ω,$ and

$X_{C} = \frac{1}{C ω} = \frac{1}{0.1 \times 1 0^{- 12} \times 100 π} = \frac{1 0^{11}}{π} Ω$

Since X_C is approximately infinite, so the phase angle between current and supplied voltage and the nature of the circuit is $\approx 90 °,$ predominantly capacitive circuit.

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For a series LCR circuit with R = 100 $Ω$ , L = 0.5mH and C = 0.1 pF connected across 220V – 50Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is:

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For a series LCR circuit with R = 100 Ω , L = 0.5mH and C = 0.1 pF connected across 220V – 50Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is:

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For a series LCR circuit with R = 100 $Ω$ , L = 0.5mH and C = 0.1 pF connected across 220V – 50Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is: