Physics Alternating Current Alternating Current Overview Class 12th Physics

For a series LCR circuit with R = 100 $Ω$ , L = 0.5mH and C = 0.1 pF connected across 220V – 50Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mo>≈</mo> <mn>9</mn> <mn>0</mn> <mo>°</mo> <mo>,</mo> </mrow> </math> </span> predominantly inductive circuit</p>

Option 2 - <p>0°, resonance circuit</p>

Option 3 - <p><span contenteditable="false"> <math> <mrow> <mo>≈</mo> <mn>9</mn> <mn>0</mn> <mo>°</mo> <mo>,</mo> </mrow> </math> </span>predominantly capacitive circuit</p>

Option 4 - <p>0°, resistive circuit</p>

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 3

Detailed Solution:

$ω = 100 π, R = 100 Ω, X_{L} = L ω = 0.5 * 1 0^{- 3} * 100 π = 5 π * 1 0^{- 2} Ω,$ and

$X_{C} = \frac{1}{C ω} = \frac{1}{0.1 * 1 0^{- 12} * 100 π} = \frac{1 0^{11}}{π} Ω$

Since X_C is approximately infinite, so the phase angle between current and supplied voltage and the nature of the circuit is $\approx 90 °,$ predominantly capacitive circuit.

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