From a circular ring of mass ' M ' and radius ' R ' an arc corresponding to a 90° sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is ' K ' times ' MR² '. Then the value of ' K ' is:
From a circular ring of mass ' M ' and radius ' R ' an arc corresponding to a 90° sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is ' K ' times ' MR² '. Then the value of ' K ' is:
Option 1 -
3/4
Option 2 -
7/8
Option 3 -
1/4
Option 4 -
1/8
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:Kindly go through the solution
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