Gravitational force between two point masses is found to be&nbsp;F when both are in vacuum. If both the masses are immersed in water, new gravitational force will be:

Information insufficient

Ask & Answer Question

Overview Physics Gravitation Physics Class 11th

Gravitational force between two point masses is found to be F when both are in vacuum. If both the masses are immersed in water, new gravitational force will be:

Option 1 -

Greater than F

Option 2 -

Less than F

Option 3 -

Option 4 -

Information insufficient

1 View | Posted a week ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a week ago

Correct Option - 3

Detailed Solution:

Gravitational force does not depend on the surrounding medium.

0 Upvotes 0 Downvotes

Similar Questions for you

At a point away from planet of radius 6400 km, the gravitational potential and field are –6.4 × 10⁷ SI units and 6.4 SI units respectively. Find height of that point above surface of planet.

alok kumar singh

$\frac{G M}{r} = 6.4 * 1 0^{7}$ . (i)

$\frac{G M}{r^{2}} = 6.4$ . (ii)

$r = \frac{6.4 * 1 0^{7}}{6.4}$

= 10⁷ m

= 10,000 km

R + h = 10,000

h = 10,000 – 6400 = 3600 km

Mass of moon is $\frac{1}{81}$ times the mass of a planet and radius is $\frac{1}{9}$ times the radius of the planet. The ratio of escape speed from planet to escape speed from moon is ________.

alok kumar singh

-> $V_{e s c} = \sqrt[]{\frac{2 G M}{R}}$

$R a t i o = \sqrt[]{\frac{81}{9}} = 3$

If the gravitational acceleration at the surface of earth is g, then increase in potential energy in lifting an object of mass m from earth surface to a height equal to half of radius of earth from surface will be:

alok kumar singh

Determine the energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 3R.

alok kumar singh

Suppose the gravitational force varies inversely as the $n^{t h}$ power of distance. Then, time period of a planet in circular orbit of radius R around the sum will be proportional to

alok kumar singh

Given $F \propto \frac{1}{r^{n}}$

$m ω^{2} R = \frac{K}{R^{n}}$

$? \frac{m . 4 π^{2} R}{T^{2}} = \frac{K}{R^{n}}$

$? T^{2} \propto R^{n + 1}$

$T \propto R^{\frac{n + 1}{2}}$

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
688k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Gravitational force between two point masses is found to be F when both are in vacuum. If both the masses are immersed in water, new gravitational force will be:

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question