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If λ1  and  λ2 are the wavelengths of the third member of Lyman and first member of Paschen series respectively, then the value of λ1:λ2  is:

Option 1 -

1 :3

Option 2 -

7 : 108 

Option 3 -

1 : 9

Option 4 -

7 : 135

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    Lyman Series nf = 1, ni = 2, 3.

    Paschen series nf = 3, ni = 4, 5, 6 -

    1λ1=RZ2 (112−142)

    1λ2=RZ2 (132−142)

    1/λ11/λ2=1−11619−116⇒λ2λ1=151679×16=15×97⇒λ1λ2=7135

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