If a particle starting from rest having constant acceleration covers distance S1 in first (p – 1) seconds and S2 in first p seconds, then determine time for which displacement is S1 + S2
If a particle starting from rest having constant acceleration covers distance S1 in first (p – 1) seconds and S2 in first p seconds, then determine time for which displacement is S1 + S2
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <mn>2</mn> <msup> <mrow> <mi>p</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> <mo>+</mo> <mn>1</mn> <mo>−</mo> <mn>2</mn> <mi>p</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <mn>2</mn> <msup> <mrow> <mi>p</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> <mo>+</mo> <mn>1</mn> <mo>+</mo> <mn>2</mn> <mi>p</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <msup> <mrow> <mrow> <mo>(</mo> <mrow> <mi>p</mi> <mo>+</mo> <mn>1</mn> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>2</mn> </mrow> </msup> <mo>−</mo> <mi>p</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 4 - <p>2p</p>
3 Views|Posted 4 months ago
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1 Answer
A
Answered by
4 months ago
Correct Option - 1
Detailed Solution:
S1 =
S2 =
S1 + S2 =
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Physics Motion in Straight Line 2025
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