If an average person jogs, he produces 14.5 * 103 cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 * 103 cal for evaporation) is
(a) 0.25 kg
(b) 2.25 kg
(c) 0.05 kg
(d) 0.20 kg
If an average person jogs, he produces 14.5 * 103 cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 * 103 cal for evaporation) is
(a) 0.25 kg
(b) 2.25 kg
(c) 0.05 kg
(d) 0.20 kg
3 Views|Posted 7 months ago
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1 Answer
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Answered by
7 months ago
This is a multiple choice answer as classified in NCERT Exemplar
(a) Amount of sweat evaporated /minute =
=
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physics ncert solutions class 11th 2023
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