If speed V, area A and force F are chosen as fundamental units, then the dimension of Young's modulus will be

Option 1 - FA²V⁻³

Option 2 - FA²V⁻²

Option 3 - FA²V⁻¹

Option 4 - FA⁻¹V⁰

3 Views|Posted 7 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

7 months ago

Correct Option - 4

Detailed Solution:

Y ∝ F? V? A? Y = (E/A)/L²
ML? ¹T? ² ∝ (M¹L¹T? ²)? (L¹T? ¹)? (L²)?
a=1, a+b+2c=-1, -2a-b=-2
a=1, b=0, c=-1
Y = F¹V? A? ¹

Upvote

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.9L

Reviews

1.8M

Answers

Search from Shiksha's 1 lakh+ Topics

See what others like you are asking & answering