If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
[Take g = 10 ms⁻², the radius of earth, R = 6400*10³ m, Take π = 3.14]
If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
[Take g = 10 ms⁻², the radius of earth, R = 6400*10³ m, Take π = 3.14]
Option 1 - <p>1200 minutes<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>Does not change<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>60 minutes<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>84 minutes<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
4 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
Answered by
5 months ago
Correct Option - 2
Detailed Solution:
g? = g - ω²R ⇒ 0 = g - ω²R ⇒ ω = √ (g/R)
⇒ T = 2π/ω = 2π√ (R/g) = 2 * 3.14 * √ (6400 * 10³)/10)
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