If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
[Take g = 10 ms⁻², the radius of earth, R = 6400×10³ m, Take π = 3.14]
If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
[Take g = 10 ms⁻², the radius of earth, R = 6400×10³ m, Take π = 3.14]
Option 1 -
1200 minutes
Option 2 -
Does not change
Option 3 -
60 minutes
Option 4 -
84 minutes
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1 Answer
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Correct Option - 2
Detailed Solution:g? = g - ω²R ⇒ 0 = g - ω²R ⇒ ω = √ (g/R)
⇒ T = 2π/ω = 2π√ (R/g) = 2 × 3.14 × √ (6400 × 10³)/10)
Similar Questions for you
. (i)
. (ii)
= 107 m
= 10,000 km
R + h = 10,000
h = 10,000 – 6400 = 3600 km
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