If the distance between successive compressions and rarefaction in a sound wave is 2 m and velocity of sound is 360 m/s, then the frequency is
If the distance between successive compressions and rarefaction in a sound wave is 2 m and velocity of sound is 360 m/s, then the frequency is
Option 1 - <p>180 Hz</p>
Option 2 - <p>45 Hz</p>
Option 3 - <p>120 Hz</p>
Option 4 - <p>90 Hz</p>
10 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
A
Answered by
4 months ago
Correct Option - 4
Detailed Solution:
Distance between successive compression and rarefaction is λ/2
.
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