If the electric potential at any point (x, y, z)m in space is given by V = 3x2 volt. The electric field at the point (1, 0, 3)m will be:

According to relation between field and potential, we can write E → = − d V d x ( i ^ ) = − d ( 3 x 2 ) d x ( i ^ ) = − 6 x ( i ^ ) E → ( 1 , 0 , 3 ) = − 6 ( i ^ ) N / C

If the electric potential at any point (x, y, z)m in space is given by V = 3x2 volt. The electric field at the point (1, 0, 3)m will be:

6 Vm-1, directed along positive x-axis.

3 Vm-1, directed along positive x-axis.

3 Vm-1, directed along negative x-axis.

6 Vm-1, directed along negative x-axis.

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Electrostatics Physics Electrostatic Potential and Capacitance Physics Class 12th

If the electric potential at any point (x, y, z)m in space is given by V = 3x² volt. The electric field at the point (1, 0, 3)m will be:

Option 1 -

3 Vm^-1, directed along positive x-axis.

Option 2 -

3 Vm^-¹, directed along negative x-axis.

Option 3 -

6 Vm^-1, directed along positive x-axis.

Option 4 -

6 Vm^-¹, directed along negative x-axis.

2 Views | Posted 2 weeks ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 weeks ago

Correct Option - 3

Detailed Solution:

According to relation between field and potential, we can write

^{$\vec{E} = - \frac{d V}{d x} (\hat{i}) = - \frac{d (3 x^{2})}{d x} (\hat{i}) = - 6 x (\hat{i})$}

^{${\vec{E}}_{(1, 0, 3)} = - 6 (\hat{i}) N / C$}

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