If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is x 2 times its original time period. Then the value of x  is:

Option 1 - <p><span contenteditable="false"> <math> <mrow> <mroot> <mrow> <mn>3</mn> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 2 - <p><span contenteditable="false"> <math> <mrow> <mroot> <mrow> <mn>2</mn> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 3 - <p><span contenteditable="false"> <math> <mrow> <mn>2</mn> <mroot> <mrow> <mn>3</mn> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 4 - <p>4</p>
2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 2
Detailed Solution:

T = 2 π ? g where t = l 2

T = 2 π t g

T = x 2 T

2 π t 2 g = x 2 2 π t g

1 2 = x 2 x = 2

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Physics Oscillations 2025

Physics Oscillations 2025

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