Class 11th Physics Oscillations Physics NCERT Exemplar Solutions Class 11th Chapter Fifteen Physics Simple Harmonic Motion

If the time period of a two meter long simple pendulum is 2s, the acceleration due to gravity at the place where pendulum is executing S.H.M. is:

Option 1 - <p>9.8 ms<sup>-2</sup></p>

Option 2 - <p>16 m/s<sup>2</sup></p>

Option 3 - <p>2π<sup>2</sup> ms<sup>-2</sup></p>

Option 4 - <p>2π<sup>2</sup> ms<sup>-2</sup></p>

2 Views|Posted 6 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 3

Detailed Solution:

$T = 2 π \sqrt[]{\frac{l}{g}}$

$\Rightarrow 2 = 2 π \sqrt[]{\frac{2}{g}}$

$\Rightarrow g = 2 π^{2} m / s^{2}$

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