If wavelength corresponding to 2nd line of Lyman series is l, then the wavelength corresponding to last line of Balmer series will be:
If wavelength corresponding to 2nd line of Lyman series is l, then the wavelength corresponding to last line of Balmer series will be:
Option 1 -
9λ/8
Option 2 -
32λ/9
Option 3 -
27λ/16
Option 4 -
24λ/7
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1 Answer
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Correct Option - 2
Detailed Solution:
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Change in surface energy = work done
|DE0| = –10.2

]
= 3 m/s
n = 4
Number of transitions =
Kinetic energy: Potential energy = 1 : –2
Kindly go through the solution
rn? µn2
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