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If x=5sin(πt+π3)m  represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are

Option 1 -

5 cm, 2s

Option 2 -

5 m, 2s

Option 3 -

5 cm, 1s

Option 4 -

5 m, 1s

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 2


    Detailed Solution:

    x=5sin (πt+π3)m

    Amplitude  =5 m

    =5 m

    ω = π = 2 π T

    T=2ππ=2 s

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