If you are provided a set of resistance 2 $\Omega$ , 4 $\Omega$ , 6 $\Omega$ and 8 $\Omega$ . Connected these resistances so as to obtain an equivalent resistance of $\frac{46}{3}\Omega .$

<p><span contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>R</mi> </mrow> <mrow> <mi>e</mi> <mi>q</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mrow> <mn>2</mn> <mo>×</mo> <mn>4</mn> </mrow> <mrow> <mn>2</mn> <mo>+</mo> <mn>4</mn> </mrow> </mfrac> <mo>+</mo> <mn>6</mn> <mo>+</mo> <mn>8</mn> <mo>=</mo> <mfrac> <mrow> <mn>4</mn> <mn>6</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> <mi>Ω</mi> </mrow> </math> </span></p>

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