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In a photoelectric experiment ultraviolet light o wavelength 280nm is used with lithium cathode having work function ? = 2.5eV. If the wavelength of incident light is switched to 400nm, find out the change in the stopping potential. (h = 6.63 × 10-34 Js, c = 3 × 108 ms-1)

Option 1 -

1.3V

Option 2 -

1.1V

Option 3 -

0.6V

Option 4 -

1.9V

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 1


    Detailed Solution:

    h c λ 1 = W + e V 1

    h c λ 2 = W + e V 2

    = 1 2 4 0 0 ( 1 2 8 0 0 − 1 4 0 0 0 ) [ λ 1 & λ 2 a r e     t a k e n     i n     A ° ]

    = 4 . 4 − 3 . 1 = 1 . 3 V

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