In a reactor, 2 kg of ₉₂U²³⁵ fuel is fully used up in 30 days. The energy released per fission is 200MeV. Given that the Avogadro number, N = 6.023 × 10²⁶ per kilo mole and 1eV = 1.6 × 10⁻¹⁹ J. The power output of the reactor is close to:
(A) 60MW
In a reactor, 2 kg of ₉₂U²³⁵ fuel is fully used up in 30 days. The energy released per fission is 200MeV. Given that the Avogadro number, N = 6.023 × 10²⁶ per kilo mole and 1eV = 1.6 × 10⁻¹⁹ J. The power output of the reactor is close to:
(A) 60MW
Option 1 -
60MW
Option 2 -
35MW
Option 3 -
125MW
Option 4 -
54MW
Asked by Shiksha User
-
1 Answer
-
Correct Option - 1
Detailed Solution:P = E/t
= 2/235 × (6.023×10²? ×200×1.6×10? ¹? )/ (30×24×60×60) = 60W
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers