In adiabatic process, the density of a diatomic gas becomes 32 times its initial value. The final pressure of the gas is found to be times the initial pressure. The value of is:
In adiabatic process, the density of a diatomic gas becomes 32 times its initial value. The final pressure of the gas is found to be times the initial pressure. The value of is:
Option 1 - <p>128</p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mn>32</mn> </mrow> </mrow> </mfrac> </math> </span></p>
Option 3 - <p>32</p>
Option 4 - <p>326</p>
2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
Answered by
6 months ago
Correct Option - 1
Detailed Solution:
In adiabatic process
PV? = constant
P (m/ρ)? = constant
As mass is constant
P ∝ ρ?
P_f/P_i = (ρ_f/ρ_i)? = (32)? /? = 2? = 128
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