In an experiment of find out diameter of wire using screw gauge, the following observations were noted:
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(A) Screw moves 0.5mm on main scale in one complete rotation
(B) Total divisions on circular scale = 50
(C) Main scale reading is 2.5 mm
(D) 45th division of circular scale is in the pitch line
(E) Instrument has 0.03 mm negative error
Then the diameter of wire is:
In an experiment of find out diameter of wire using screw gauge, the following observations were noted:
(A) Screw moves 0.5mm on main scale in one complete rotation
(B) Total divisions on circular scale = 50
(C) Main scale reading is 2.5 mm
(D) 45th division of circular scale is in the pitch line
(E) Instrument has 0.03 mm negative error
Then the diameter of wire is:
Option 1 -
2.92 mm
Option 2 -
2.54 mm
Option 3 -
2.98 mm
Option 4 -
3.45 mm
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:MS – Reading = 2.5 mm.
50 division on CS = 0.5 mm on MS.
= .45 mm on M.S.
So, diameter = 2.5 mm
+0.45 mm
+0.03 mm
= 2.98 mm
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