In an experiment to determine the Young’s modulus of wire of a length exactly 1m, the extension in the length of the wire is measured as 0.4mm with an uncertainty of ± 0.02mm when a load of 1kg is applied. The diameter of the wire is measured as 0.4mm with an uncertainty of ± 0.02mm. The error in the measurement of Young’s modulus (ΔY) is found to be x × 1010Nm-2. The value of x is _________.

(take g = 10 ms-2)

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    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago

    L = 1 m

    ΔL=0.4×103m

    m=1kg

    d = 0.4 × 10-3 m

    FA=yΔLL

    y=FLAΔL= (mg)×1 (πd24)×0.4×103

    Δy=0.1×0.199×1012=1.99×1010

    = 1.99

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