In an experiment to verigy Newton's law of cooling, a graph is plotted between, the temperature difference ( Δ T ) of the water and surrounding and time as shown in figure. The initial temperature of water is taken as 8 0 ° C .  The value of t2 as mentioned in the graph will be _______.

 

10 Views|Posted 4 months ago
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4 months ago

d T d t = k ( T T 0 )  

d T ( T T 0 ) = k d t  

k = 1 6 l n ( 2 3 )             - (1)

Now d T d t = k ( T T 0 )

t = 10.257

t2 = 6 + 10.257 = 16.257 minutes

16.25 and or 16

 

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Physics NCERT Exemplar Solutions Class 11th Chapter Eight 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Eight 2025

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