In the figure, a very large plane sheet of positive charge is shown. P1 and P2 are two points at distance $\mathcal{l}and2\mathcal{l}$ $$ from the charge distribution. If $\sigma$ $$ is the surface charge density, then the magnitude of electric fields E1 and E2 at P1 and P2 respectively are:

 

Correct Option - 3


Detailed Solution:

(Independent of distance)

$E_1=E_2=\frac{\sigma }{2{\in }_0}$

<div class="photo-widget-full"><div class="figure"><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1757387961phpIChhNj.jpeg" alt="" width="341" height="150" loading="lazy"></picture></div></div><p> (Independent of distance)</p><p><span contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>E</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msub> <mo>=</mo> <msub> <mrow> <mi>E</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>=</mo> <mfrac> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <msub> <mrow> <mo>∈</mo> </mrow> <mrow> <mn>0</mn> </mrow> </msub> </mrow> </mfrac> </mrow> </math> </span></p></div></div>

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