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Alternating Current Overview Physics Alternating Current Physics Class 12th

In the given circuit the AC source has $ω = 100 r a d s^{- 1} .$ Considering the inductor and capacitor to be the current I flowing through the circuit?

Option 1 -

5.9A

Option 2 -

4.24A

Option 3 -

Option 4 -

0.94A

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Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 2

Detailed Solution:

Let, current through inductor,

$i_{L} = l_{L} s i n (ω t + ?_{1})$

$l_{L} = \frac{200 \sqrt[]{2}}{\sqrt[]{5 0^{2} + {(100 \times 0.50)}^{2}}} = 4 A$

$?_{1} = t a n^{- 1} (\frac{- 100 \times 0.50}{50}) = - \frac{π}{4}$

Let, current through capacitor,

As $?_{2} - ?_{1} = \frac{π}{2}$

$l = \sqrt[]{{(I_{L})}^{2} + {(I_{C})}^{2}}$

$= \sqrt[]{4^{2} + 2^{2}} = 4.47 A$

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In the given circuit the AC source has $ω = 100 r a d s^{- 1} .$ Considering the inductor and capacitor to be the current I flowing through the circuit?