In the given figure, a body of mass M is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to firm supports. If each spring has spring constant k, the frequency of oscillation of given body is:

Option 1 -

$\frac{1}{2 π} \sqrt[]{\frac{k}{2 m}}$

Option 2 -

$\frac{1}{2 π} \sqrt[]{\frac{k}{M g s i n α}}$

Option 3 -

$\frac{1}{2 π} \sqrt[]{\frac{2 k}{M}}$

Option 4 -

$\frac{1}{2 π} \sqrt[]{\frac{2 k}{M g s i n α}}$

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

Here, $K_{e q} = 2 k$ $_{}$

$T = 2 π \sqrt[]{\frac{m}{2 k}}$

$∴ f = \frac{1}{2 π} \sqrt[]{\frac{2 k}{m}}$

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