It is found that |A+B|=|A|. This necessarily implies,
(a) B = 0
(b) A,B are antiparallel
(c) A,B are perpendicular
(d) A.B ≤ 0
It is found that |A+B|=|A|. This necessarily implies,
(a) B = 0
(b) A,B are antiparallel
(c) A,B are perpendicular
(d) A.B ≤ 0
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- b, d
Explanation – given A+B+C = 0
B
B +B =0
B
B
A
(A )
It cannot be zero
(b) (A ).C= (B ).C=0 . if b|C then B =0 then (B )
(c) (A )=X=ABsin . The direction of X is perpendicular to the plane containing A and B (A )
(d) if c2= A2+B2, then angle between A and B is 900
(A ).C= (AB sin900X).C=AB (X.C)
= ABC cos900= 0
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