Let η 1 is the efficiency of an engine at T1 = 4 4 7 ° C and T2 = 1 4 7 ° C while η 2 is the efficiency at T1 = 9 4 7 ° C and T2 4 7 ° C . The ratio η 1 η 2 will be

As we know that η=1−T2T1, so n1n2=0.420.74≈0.56

Let $η_{1}$ is the efficiency of an engine at T₁ = $447 ° C$ and T₂ = $147 ° C$ while $η_{2}$ is the efficiency at T₁ = $947 ° C$ and T₂ $47 ° C$ . The ratio $\frac{η_{1}}{η_{2}}$ will be

Option 1 - 0.41

Option 2 - 0.56

Option 3 - 0.73

Option 4 - 0.70

2 Views|Posted 7 months ago

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7 months ago

Correct Option - 2

Detailed Solution:

As we know that

$η = 1 - \frac{T_{2}}{T_{1}}, s o$

$\frac{n_{1}}{n_{2}} = \frac{0.42}{0.74} \approx 0.56$

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