Let there be n resistors R1 . . . 𝑅 𝑛 with 𝑅 max = max ( R1 . . . . 𝑅 ) and R min = min { R1 . . . R n }. Show that when they are connected in parallel the resultant resistance R p = R min 𝑅 𝑝 = 𝑅 min and when they are connected in series, the resultant resistance Rs > Rmax . Interpret the result physically.

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This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation-Β when all resistance are in parallel

1 R p = 1 R 1 + … … … … . . + 1 R n by multiplying this equation by Rmin we have

R m i n R p = R m i n R 1 + … … … … . . + R m i n R n

But there exist a term in RHSΒ RminRmin=1Β and other terms are positive so we have

Β 

R m i n R p = R m i n R 1 + … … … … . . + R m i n R n >1

This shows that equivalent resistance is less than maximum

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Physics NCERT Exemplar Solutions Class 12th Chapter Three 2025

Physics NCERT Exemplar Solutions Class 12th Chapter Three 2025

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