Light enters form air into a given medium at angle of 45° with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of 15° from its original direction. The refractive index of the medium is

Option 1 -

1.732 

Option 2 -

1.333          

Option 3 -

1.414 

Option 4 -

2.732

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago
    Correct Option - 3


    Detailed Solution:

    Using snell’s law –

    sin I = μsinr

    sin45° = μsin30°

    μ=sin45sin30=12×2=√2

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