Search Colleges, Courses, Exams, Questions and Articles

Ask a query on 8879100846 Ask Login | Sign Up

 

 

› Ask & Answer › Question

Mass of Bromine, Selenium and Krypton are given as:-

Option 1 -

all 3

Option 2 -

(i) & (iii) only

Option 3 -

(ii) & (iii) only

Option 4 -

(i) & (ii) only

0 4 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    Q ( i ) = ( M B r − M K r ) c 2 > 0

    Q ( i i ) = ( M B r − M S e − 2 M e ) c 2 > 0 Q ( i i ) = ( M B r − M s e ) c 2 > 0

Similar Questions for you

Determine the number of nuclei that will be decayed upto one average life of radioactive material? (N0 : Initial number of nuclei)

 
A
alok kumar singh

N = N0e–λt

->t = λN = N0/e

So number of nuclei decayed = N0 – N

= N0 (1- 1/e) 

Density of nucleus is of the order of
A
alok kumar singh

Density of nuclei is order of 1017 kg m–3.

Power factor of series LCR circuit at resonance is
A
alok kumar singh

Kindly go through the solution '

 

Density of nucleus is of the order of
V
Vishal Baghel

Density of nuclei is order of 1017 kg m-3.

Two radioactive substances X and Y originally have N1 and N2 nuclei respectively. Half life of X is half of the life of Y. After three half lives of Y, number of nuclei of both are equal.

The ratio  N 1 N 2  will be equal to:
V
Vishal Baghel

Number of half lives of Y = 3

Number of half lives of X = 6 [As half life of X is half of that of Y].

N 1 2 6 = N 2 2 3 ⇒ N 1 N 2 = 8

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 682k Reviews
  • 1800k Answers

Learn more about...

Share Your College Life Experience

Write a Review

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Ask Now
Community GuidelinesUser Points System
QuestionsDiscussionsTags
×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post