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Metallic disc of inner radius R and outer radius 2R is rotating with an angular speed ω. What will be the electric potential difference that appears between the inner and outer periphery. The mass of electrons is m and charge is e.

Option 1 -

(3mω²R²)/(2e)

Option 2 -

(mω²R²)/(2e)

Option 3 -

(mω²R²)/(3e)

Option 4 -

(2mω²R²)/e

0 5 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    eE = e (dV/dr) = mω²r
    ΔV = ∫dV = ∫ (m/e)ω²rdr from R to 2R
    ΔV = (3mω²R²)/ (2e)

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