Molecules of an ideal gas are known to have three translational degrees of freedom and two rotational degrees of freedom. The gas is maintained at a temperature of T. The total internal energy, U of a mole of this gas, and the value of γ (=C?/C?) are given, respectively, by:
Molecules of an ideal gas are known to have three translational degrees of freedom and two rotational degrees of freedom. The gas is maintained at a temperature of T. The total internal energy, U of a mole of this gas, and the value of γ (=C?/C?) are given, respectively, by:
Option 1 - <p>U = (5/2)RT and γ = 6/5</p>
Option 2 - <p>U = 5RT and γ = 7/5<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>U = (7/2)RT and γ = 7/5<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>U = (5/2)RT and γ = 7/5</p>
6 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
Answered by
6 months ago
Correct Option - 3
Detailed Solution:
f=5
∴ U = (5/2)RT
And γ = 1+2/f = 1+2/5=7/5
Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Heat is path dependent so path function but internal energy does not depend on path chosen.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...
Didn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering






