Moment of inertia (M.I) of four bodies, having same mass and radius, and reported as:
I1 = M.I. of thin circular ring about its diameter
I2 = M.I. of circular disc about an axis perpendicular to disc and going through the centre,
I3 = M.I. of solid cylinder about its axis and
I4 = M.I. of solid sphere about its diameter.
Moment of inertia (M.I) of four bodies, having same mass and radius, and reported as:
I1 = M.I. of thin circular ring about its diameter
I2 = M.I. of circular disc about an axis perpendicular to disc and going through the centre,
I3 = M.I. of solid cylinder about its axis and
I4 = M.I. of solid sphere about its diameter.
Option 1 -
I1 + I3 < I2 + I4
Option 2 -
I1 = I2 = I3 < I4
Option 3 -
I1 = I2 = I3 > I4
Option 4 -
Asked by Shiksha User
-
1 Answer
-
Correct Option - 3
Detailed Solution:
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers