Moment of inertia (M.I) of four bodies, having same mass and radius, and reported as:

I1 = M.I. of thin circular ring about its diameter

I2 = M.I. of circular disc about an axis perpendicular to disc and going through the centre,

I3 = M.I. of solid cylinder about its axis and

I4 = M.I. of solid sphere about its diameter.

Option 1 - <p>I<sub>1</sub> + I<sub>3</sub> &lt; I<sub>2</sub> + I<sub>4</sub></p>
Option 2 - <p>I<sub>1</sub> = I<sub>2</sub> = I<sub>3</sub> &lt; I<sub>4</sub></p>
Option 3 - <p>I<sub>1</sub> = I<sub>2</sub> = I<sub>3</sub> &gt; I<sub>4</sub></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msub> <mo>+</mo> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>=</mo> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> <mo>+</mo> <mfrac> <mrow> <mn>5</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> </math> </span></p>
2 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago
Correct Option - 3
Detailed Solution:

l 1 = 1 2 m r 2

l 2 = 1 2 m r 2 l 3 = 1 2 m r 2 l 4 = 2 5 m r 2

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Physics System of Particles and Rotational Motion 2025

Physics System of Particles and Rotational Motion 2025

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