Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments ‘B’ and ‘C’ of mass numbers 105 and 115. The binding energy of nucleons in (B) and ‘C’ 6.4 MeV per nucleon. The energy Q released per fission will be :

Option 1 -

0.8 MeV

Option 2 -

275 MeV

Option 3 -

220 MeV

Option 4 -

176 MeV

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

    A 1 0 5 B + 1 1 5 C

    Q = [ 1 0 5 × 6 . 4 + 1 1 5 × 6 . 4 ] [ 2 2 0 × 5 . 6 ] M e v

    Q = 176 MeV

Similar Questions for you

A
alok kumar singh

N N0eλt

->t = λN = N0/e

So number of nuclei decayed = N0N

N0 (1- 1/e) 

A
alok kumar singh

Density of nuclei is order of 1017 kg m–3.

A
alok kumar singh

Kindly go through the solution '

 

V
Vishal Baghel

Density of nuclei is order of 1017 kg m-3.

V
Vishal Baghel

Number of half lives of Y = 3

Number of half lives of X = 6 [As half life of X is half of that of Y].

N 1 2 6 = N 2 2 3 N 1 N 2 = 8

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