Particle A of mass mA=m2 moving along the x -axis with velocity v0 collides elastically with another particle B at rest having mass mB=m3 . If both particles move along the x axis after the collision, the change Δλ in de-Broglie wavelength of particle A , in terms of its de-Broglie wavelength λ0 before collision is:

Option 1 - <p><span contenteditable="false"> <math> <mi mathvariant="normal">Δ</mi> <mi>λ</mi> <mo>=</mo> <mfrac> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </mfrac> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mn>0</mn> </mrow> </mrow> </msub> </math> </span></p>
Option 2 - <p><span contenteditable="false"> <math> <mi mathvariant="normal">Δ</mi> <mi>λ</mi> <mo>=</mo> <mfrac> <mrow> <mrow> <mn>5</mn> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </mfrac> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mn>0</mn> </mrow> </mrow> </msub> </math> </span></p>
Option 3 - <p><span contenteditable="false"> <math> <mi mathvariant="normal">Δ</mi> <mi>λ</mi> <mo>=</mo> <mn>2</mn> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mn>0</mn> </mrow> </mrow> </msub> </math> </span></p>
Option 4 - <p><span contenteditable="false"> <math> <mi mathvariant="normal">Δ</mi> <mi>λ</mi> <mo>=</mo> <mn>4</mn> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mn>0</mn> </mrow> </mrow> </msub> </math> </span></p>
5 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
A
8 months ago
Correct Option - 4
Detailed Solution:

V?1=2Ucm?-U1?2m/2Vom2+m3-Vo

65Vo-VoV05

λo=hcm2Voλf=hcM2Vo5

Δλ=8hcmVo

 

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Physics NCERT Exemplar Solutions Class 12th Chapter Six 2025

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