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Gravitation physics ncert solutions class 11th Physics Class 11th Physics NCERT Exemplar Solutions Class 11th Chapter Eight

Particles of masses 2M, m and M are respectively at points A, B and C with AB = ½ (BC). m is much-much smaller than M and at time t = 0, they are all at rest (Fig. 8.1). At subsequent times before any collision takes place:

(a) m will remain at rest.

(b) m will move towards M.

(c) m will move towards 2M.

(d) m will have oscillatory motion.

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alok kumar singh | Contributor-Level 10

4 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer-c

Explanation- force on B due to A = F_BA= $\frac{G (2 M m)}{{A B}^{2}}$

force on B due to C = F_BC= $\frac{G (M m)}{{B C}^{2}}$

BC = 2AB

F_BC= $\frac{G (M m)}{(2 {A B)}^{2}} = \frac{G (M m)}{4 {A B}^{2}}$ BA

So it move towards BA

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